P(\text{at least one of each color}) = \frac{630}{1365}
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- ### Step 3: Total favorable outcomes
- \text{Favorable} = 210 + 315 + 105 = 630
- ### Step 4: Compute the probability
- \frac{630}{1365} = \frac{6}{13}
- \boxed{\frac{6}{13}}
- Question: A transportation analyst is analyzing a network with 6 red buses, 4 green buses, and 5 blue buses. If she randomly selects 5 buses for maintenance, what is the probability that she selects at least two buses of each color?
