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/ p + q + r &= 10 \quad \text{(1)}\\
p + q + r &= 10 \quad \text{(1)}\\
February 22, 2026
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\( p(2)^2 + q(2) + r = 18 \implies 4p + 2q + r = 18 \)
\( p(3)^2 + q(3) + r = 30 \implies 9p + 3q + r = 30 \)
System:
4p + 2q + r &= 18 \quad \text{(2)}\\
9p + 3q + r &= 30 \quad \text{(3)}
Substitute \( p = 2 \) into (4):
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