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#### 165
A bank account has an initial balance of $1000 and earns 5% interest compounded annually. What is the balance after 3 years?
Use the compound interest formula: \(A = P(1 + r)^n\).
Here, \(P = 1000\), \(r = 0.05\), and \(n = 3\).
\(A = 1000 \times (1 + 0.05)^3 = 1000 \times 1.157625 = 1157.625\).
Solve for \(x\) in the equation \(3x^2 - 12x + 9 = 0\).
Factor the quadratic equation: \(3(x^2 - 4x + 3) = 0\).
Factor further: \(3(x - 3)(x - 1) = 0\).
Set each factor to zero: \(x - 3 = 0\) or \(x - 1 = 0\).
Solutions are \(x = 3\) or \(x = 1\).