aminah nieves

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A bank account has an initial balance of $1000 and earns 5% interest compounded annually. What is the balance after 3 years?

Use the compound interest formula: $A = P(1 + r)^n$.

Here, $P = 1000$, $r = 0.05$, and $n = 3$.

$A = 1000 \times (1 + 0.05)^3 = 1000 \times 1.157625 = 1157.625$.

Solve for $x$ in the equation $3x^2 - 12x + 9 = 0$.

Factor the quadratic equation: $3(x^2 - 4x + 3) = 0$.

Factor further: $3(x - 3)(x - 1) = 0$.

Set each factor to zero: $x - 3 = 0$ or $x - 1 = 0$.

Solutions are $x = 3$ or $x = 1$.

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