الحل: ليكن $\mathbf{M} = \begin{pmatrix} a & b \\ c & d \end{pmatrix}$. نحتاج إلى إيجاد $a$, $b$, $c$, و $d$ بحيث:
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- الآن، لنفترض $c = 3$, إذن:
- السؤال: أوجد جميع الزوايا $z \in [0^\circ, 360^\circ]$ التي تحقق المعادلة $2\sin z + \sqrt{3} = 0$.
- الزوايا $z$ التي تحقق $\sin z = -\frac{\sqrt{3}}{2}$ تقع في الربعين الثالث والرابع. الزاوية المرجعية هي $60^\circ$ لأن $\sin 60^\circ = \frac{\sqrt{3}}{2}$. لذلك، الحلول في الفترة $[0^\circ, 360^\circ]$ هي:
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